Loss of precision question
byte testByte = 0xC9;
Tells me a int was found, and it could possibly loose precision, but This is indeed a byte. Am I doing something wrong?
Thanks for any help.
Seems when I do this the highest number I can get to
is 32 anything above that goes to 32 0x20
Anyone know a work around for this?Doubt it. This works perfectly
byte b = (byte)0xc9;
System.out.println("b as byte=" + b);
System.out.println("b as int=" + (0xff & b));
. And produces the following (which is more than 32.)
b as byte=-55
b as int=201